Solution Exercise 91 **: python algorithm which move all words containing a number at the end of the list

Exercise 91 **

Write an algorithm in python as a function that transforms a string text T into a list where words containing numbers are placed at the end of the list. Example if T = "Python_1 created in 1991. Currently it is in version Python_3.9"the algorithm returns the list: ['created', 'in', 'Currently', 'it', 'is', 'in', 'version', 'Python_1', '1991.', 'Python_3.9' ]

Solution

# function which tests if a given word contains a number or not
def digit_in_word (word):
    # initialization of a counter
    counter = 0
    for x in word:
        if x.isdigit():
            counter = counter + 1
            
    if counter > 0:
        return True
    else:
        return False
        
# function which transforms a string into a list by moving all words containing numbers at the end
def moveDigit (T):
    # transformation of the text string T into a list
    L = T.split ()
    
    # initialization of the list of words which do not contain any digits
    L_without_digit = []
    
    # initialization of the list of words which contain at least one digit
    L_with_digit = []
    
    # browse the elements of list L and find words that contain numbers
    for word in L:
        if digit_in_word (word):
            L_with_digit.append (word)
        else:
            L_without_digit.append (word)
            
    result = L_without_digit + L_with_digit
            
    return result

# Example
T = "Python_1 created in 1991. Currently it is in version Python_3.9"
print (moveDigit (T))
# the output is:
# ['created', 'in', 'Currently', 'it', 'is', 'in', 'version', 'Python_1', '1991.', 'Python_3.9']