Solution Exercise 48: Python algorithm that determines the sum of elements with odd index of given list

Exercise 48

Write a Python algorithm as a function that takes a list L of numbers as a parameter and returns the sum of elements of L with odd index. Example if L = [3, 2, 5, 11, 21, 4, 7], the algorithm returns the number 17.

Solution

def oddSum (L):
    n = len (L)
    # initialize the sum of elements with odd index
    s = 0
    # browsing throw elements of L and searching all elements of with odd index
    for i in range (0, n):
        if i% 2 != 0:
            s = s + L [i]
    return s
# Example
L = [3, 2, 5, 11, 21, 4, 7]
print(oddSum (L)) # the output is  17