Solution Exercise 30: Python algorithm that determines the list of words that do not contain any digits in a given text

Exercise 30

Write a Python algorithm that determines the list of words containing no digits in a given T text.

Solution

# creation of a function which detects if a word contains a number or not
def digitInWord (word):
    counter = 0
    for x in word:
        if x.isdigit():
            counter = counter + 1
    if counter> 0:
        return True
    else:
        return False

# creation of a function which returns the list of words with no digits
def noDigitInText (T):
    # initialize the list of words with no digits
    listWordWithoutNumber = []
    # convert text T to a list
    L = T.split ()
    for word in L:
        # we test if the word 'word' does not contain any digits
        # using the digitInWord function defined previously
        if not digitInWord(word):
            listWordWithoutNumber.append (word)
    return listWordWithoutNumber
# Example
T = "Python2.7 has been replaced by Python3.X since 2018"
print ("the list of words with no digit is: ", noDigitInText (T))
# returns: the list of words with no digit is:  ['has', 'been', 'replaced', 'by', 'since']