Solution Exercise 3 : python algorithm which determines the list of odd index element and the list of even index element

Exercise 3

write a python algorithm as function that takes as parameter a list l and returns a tuple of two lists (l_old , l_even) where l_even is make up by the elements of l of even index and l_old is make up by the list element of odd index. Example: if:

L = ["Python" , "Java" , "C++" , "C#" , "VB.Net" , "Javascript"]

(['Python', 'C++', 'VB.Net'], ['Java', 'C#', 'Javascript'])

Solution

def odd_event(L):
    # getting the length of list
    n = len(L)
    # initializing the even an
    l_odd = []
    l_even = []
    
    # build the even and odd list
    for i in range(0 , n):
        if( i%2 == 0):
            l_even.append(L[i])
        else:
            l_odd.append(L[i])
    
    return (l_even , l_odd)
    
    
# Example   
L = ["Python" , "Java" , "C++" , "C#" , "VB.Net" , "Javascript"]
print(odd_event(L))
# The output is : (['Python', 'C++', 'VB.Net'], ['Java', 'C#', 'Javascript'])